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- 1 mole of equimolar mixture of ferric oxalate and ferrous oxalate will . . .
1 mol of ferric oxalate is oxidized by x mol of M n O − 4 and 1 mol of ferrous oxalate is oxidized by y mol of M n O − 4 in acidic medium The ratio x y is ____ View Solution
- K_{sp} of salt A_3B_2, solubility x ,mol ,L^{-1}, is: - Toppr
A 3 B 2 is a sparingly soluble salt of molar mass M (g m o l − 1) and solubility x g L − 1 The solubility product satisfies K S P = a ( x M ) 5 The vlaue of a is ______(Integer answer)
- How do I convert from kJ kg to kJ mol? - Physics Forums
74g mol What is the heat of combustion of one gram? 35 981 kJ per gram You get 35 981 kJ when you burn one gram, and a mole is 74 grams So wouldn't burning a mole just give you 74 times as much as burning one gram? What is 35 981 multiplied by 74?
- Understanding g mol in Unit Operations Course - Physics Forums
The chemists got here first, and a "mole" (mol) is understood to be a g-mol --- had chemists been raised in religious awe of the English units system, we might have a convention in which the unspecified "mol" would be understood to be the dram, scruple, poise, oz , grain, or some other irrational mass unit times molecular mass (weight)
- Addition of a further 2 mol of H 2 gave an additional x mol of . . . - Toppr
1mol of H2 and 3 mol of I2 give rise at equilibrium to 1 5 mol of HI Addition of a further 2 mol of H2 gave an additional 1 5 mol of HI In above problem, what is K p at the temperature of the experiment
- Equilibrium Physics Help: Calculating Kp for a . . . - Physics Forums
In an experiment , b mole of hydrogen iodide were put into a sealed vessel under pressure p At equilibrium, x mole of the hydrogen iodide had dissociated , the reaction being represented by the following equation , Express in terms of b and x of Kp Homework Equations 2HI(g) <---> H2(g) + I2(g) The Attempt at a Solution Here is my solution :
- Calculte the Energy of 1 mole of photons - Help - Physics Forums
3 49E-22 kJ * the Avogadro's constant, which is 6 022 × 10E23 mol-1 And I got the answer yoohoo! Thank you so much Please explain to me why I have to multiply my answer with the Avogadro's constant to get the final answer I appreciate your help!
- The concentration of oxalic acid is X mol lit^{-1}. 40 mL of . . . - Toppr
The concentration of oxalic acid is ′ X ′ mol l i t − 1 40 m L of this solution reacts with 16 m L of 0 05 M acidified K M n O 4 What is the p H of ′ X ′ M oxalic acid solution? [Assume that oxalic acid dissociates completely ]
- If x mol L^{-1} is the solubility of KAl(SO_{4})_{2}, then K . . . - Toppr
Click here👆to get an answer to your question ️ if x mol l1 is the solubility of kalso42 then
- 1 mol of ferric oxalate is oxidized by x mol of Mn{O}_{4 . . . - Toppr
1 mol of ferric oxalate is oxidized by x mol of M n O − 4 and also 1 mol of ferrous oxalate is oxidised by y mol of M n O − 4 in acidic medium The ration x y is: 2 : 1
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